CUET · MATHS · PYQ PAPER 2025
Let \(A\) and \(B\) be \(3 \times 3\) matrices such that \(A \neq B\). If \(A^3=B^3\) and \(A^2 B=B^2 A\), then the determinant of \(A^2+B^2\) is :
- A 1
- B 4
- C \(0\)
- D \(-2\)
Answer & Solution
Correct Answer
(C) \(0\)
Step-by-step Solution
Detailed explanation
\((A^2+B^2)(A-B) = A^3 - A^2B + B^2A - B^3\) \(= (A^3 - B^3) - (A^2B - B^2A)\) \(= 0 - 0 = 0\) Since \(A \neq B\), then \(A-B \neq 0\). As \((A^2+B^2)(A-B) = 0\) and \(A-B \neq 0\), the matrix \(A^2+B^2\) must be singular. \(\det(A^2+B^2) = 0\)
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