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CUET · MATHS · PYQ PAPER 2025

Let \(A\) and \(B\) be \(3 \times 3\) matrices such that \(A \neq B\). If \(A^3=B^3\) and \(A^2 B=B^2 A\), then the determinant of \(A^2+B^2\) is :

  1. A 1
  2. B 4
  3. C \(0\)
  4. D \(-2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0\)

Step-by-step Solution

Detailed explanation

\((A^2+B^2)(A-B) = A^3 - A^2B + B^2A - B^3\) \(= (A^3 - B^3) - (A^2B - B^2A)\) \(= 0 - 0 = 0\) Since \(A \neq B\), then \(A-B \neq 0\). As \((A^2+B^2)(A-B) = 0\) and \(A-B \neq 0\), the matrix \(A^2+B^2\) must be singular. \(\det(A^2+B^2) = 0\)
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