CUET · MATHS · PYQ PAPER 2025
Let \(A=\left[a_{i j}\right]\) is given by \(A=\left[\begin{array}{ccc}1 & -1 & 2 \\ 3 & 4 & -5 \\ 2 & -1 & 3\end{array}\right]\). Then the matrix \(B=\left[b_{i j}\right]\), where \(b_{i j}\) = Minor of \(a_{i j}\) is:
- A \(\left[\begin{array}{ccc}7 & 19 & -11 \\ -1 & -1 & 1 \\ -3 & -11 & 7\end{array}\right]\)
- B \(\left[\begin{array}{ccc}7 & -19 & 11 \\ 5 & -1 & -1 \\ 2 & 11 & 7\end{array}\right]\)
- C \(\left[\begin{array}{ccc}7 & -5 & -3 \\ 19 & 1 & -11 \\ -11 & 7 & 7\end{array}\right]\)
- D \(\left[\begin{array}{ccc}7 & 19 & -11 \\ -3 & 11 & 7 \\ -2 & -1 & -1\end{array}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\begin{array}{ccc}7 & -19 & 11 \\ 5 & -1 & -1 \\ 2 & 11 & 7\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(b_{11} = (4)(3) - (-5)(-1) = 7\) \(b_{12} = (3)(3) - (-5)(2) = 19\) \(b_{13} = (3)(-1) - (4)(2) = -11\) \(b_{21} = (-1)(3) - (2)(-1) = -1\) \(b_{22} = (1)(3) - (2)(2) = -1\) \(b_{23} = (1)(-1) - (-1)(2) = 1\) \(b_{31} = (-1)(-5) - (2)(4) = -3\)…
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