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CUET · MATHS · PYQ PAPER 2025

Let \(A=\left[a_{i j}\right]\) be a square matrix, where \(a_{i j}=\left\{\begin{array}{ll}0, & \text { when } i=j \\ 1, & \text { otherwise }\end{array}\right.\)
If \(|\operatorname{adj} A|=|A|^2\), then which of the following statements are correct?
(A) A is a skew-symmetric matrix.
(B) A is a non-singular matrix.
(C) A is a square matrix of order 4.
(D) A is a symmetric matrix.
Choose the correct answer from the options given below :

  1. A (A), (B) and (C) only
  2. B (B) and (D) only
  3. C (A) and (C) only
  4. D (B), (C) and (D) only
Verified Solution

Answer & Solution

Correct Answer

(D) (B), (C) and (D) only

Step-by-step Solution

Detailed explanation

\(|\operatorname{adj} A|=|A|^{n-1}\) \(|A|^{n-1}=|A|^2\) If \(|A|=0\), then \(n-1=0 \implies n=1\). For \(n=1\), \(A=[0]\), \(|\operatorname{adj} A|=1\), \(|A|^2=0\). \(1=0\) is false. Thus, \(|A| \ne 0\). Therefore, \(n-1=2 \implies n=3\). This means (C) "A is a square matrix…
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