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CUET · MATHS · PYQ PAPER 2025

Let \(|\vec{a}|=5,|\vec{b}|=2\) and \(\vec{a} \cdot \vec{b}=6\), then the value of \(|\vec{a} \times \vec{b}|\) is equal to

  1. A 8
  2. B 6
  3. C 10
  4. D 60
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Answer & Solution

Correct Answer

(A) 8

Step-by-step Solution

Detailed explanation

\(|\vec{a} \times \vec{b}|^2 = |\vec{a}|^2 |\vec{b}|^2 - (\vec{a} \cdot \vec{b})^2\) \(|\vec{a} \times \vec{b}|^2 = (5)^2 (2)^2 - (6)^2\) \(|\vec{a} \times \vec{b}|^2 = 25 \times 4 - 36\) \(|\vec{a} \times \vec{b}|^2 = 100 - 36 = 64\) \(|\vec{a} \times \vec{b}| = \sqrt{64} = 8\)
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