CUET · MATHS · PYQ PAPER 2025
Let \(|\vec{a}|=5,|\vec{b}|=2\) and \(\vec{a} \cdot \vec{b}=6\), then the value of \(|\vec{a} \times \vec{b}|\) is equal to
- A 8
- B 6
- C 10
- D 60
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
\(|\vec{a} \times \vec{b}|^2 = |\vec{a}|^2 |\vec{b}|^2 - (\vec{a} \cdot \vec{b})^2\) \(|\vec{a} \times \vec{b}|^2 = (5)^2 (2)^2 - (6)^2\) \(|\vec{a} \times \vec{b}|^2 = 25 \times 4 - 36\) \(|\vec{a} \times \vec{b}|^2 = 100 - 36 = 64\) \(|\vec{a} \times \vec{b}| = \sqrt{64} = 8\)
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