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CUET · MATHS · PYQ PAPER 2023

It is given that mean and variance of a binomial variate X are 2 and 1 respectively. Find the probability that X takes value greater than or equal to 1.

  1. A \(\frac{1}{16}\)
  2. B \(\frac{15}{16}\)
  3. C \(\frac{11}{16}\)
  4. D \(\frac{5}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{15}{16}\)

Step-by-step Solution

Detailed explanation

\(np = 2, np(1-p) = 1 \) \(2(1-p) = 1 \Rightarrow p = \frac{1}{2} \) \(n \cdot \frac{1}{2} = 2 \Rightarrow n = 4 \) \(P(X \ge 1) = 1 - P(X=0) \) \(P(X=0) = \binom{4}{0} \left(\frac{1}{2}\right)^0 \left(\frac{1}{2}\right)^4 = \frac{1}{16} \)…
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