CUET · MATHS · PYQ PAPER 2023
It is given that mean and variance of a binomial variate X are 2 and 1 respectively. Find the probability that X takes value greater than or equal to 1.
- A \(\frac{1}{16}\)
- B \(\frac{15}{16}\)
- C \(\frac{11}{16}\)
- D \(\frac{5}{16}\)
Answer & Solution
Correct Answer
(B) \(\frac{15}{16}\)
Step-by-step Solution
Detailed explanation
\(np = 2, np(1-p) = 1 \) \(2(1-p) = 1 \Rightarrow p = \frac{1}{2} \) \(n \cdot \frac{1}{2} = 2 \Rightarrow n = 4 \) \(P(X \ge 1) = 1 - P(X=0) \) \(P(X=0) = \binom{4}{0} \left(\frac{1}{2}\right)^0 \left(\frac{1}{2}\right)^4 = \frac{1}{16} \)…
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