CUET · MATHS · PYQ PAPER 2023
Integrating factor of the differential equation \(\left(1-y^2\right) \frac{d x}{d y}+x y=a y\) is :
- A \(\frac{1}{1-y^2}\)
- B \(\frac{1}{\sqrt{y^2-1}}\)
- C \(\frac{1}{y^2-1}\)
- D \(\frac{1}{\sqrt{1-y^2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{\sqrt{1-y^2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{d x}{d y} + \frac{y}{1-y^2}x = \frac{a y}{1-y^2}\) \(P(y) = \frac{y}{1-y^2}\) \(\int P(y) dy = \int \frac{y}{1-y^2} dy = -\frac{1}{2} \ln|1-y^2|\) Integrating Factor \( = e^{\int P(y) dy} = e^{-\frac{1}{2} \ln|1-y^2|} = e^{\ln|(1-y^2)^{-1/2}|} = \frac{1}{\sqrt{1-y^2}}\)
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