CUET · MATHS · PYQ PAPER 2025
In class XII, suppose \(5 \% \) of boys and \(0.25\%\) of girls are physically fit for a game.
A fit student is selected at random from this class having same number of boys and girls.
If the probability that the selected student is a girl is \(\frac{m}{n}\), \(\operatorname{gcd}(m, n)=1\), then \(m+n\) is equal to
- A 22
- B 23
- C 24
- D 25
Answer & Solution
Correct Answer
(A) 22
Step-by-step Solution
Detailed explanation
\(P(F) = (0.05)(0.5) + (0.0025)(0.5) = 0.025 + 0.00125 = 0.02625\) \(P(G|F) = \frac{(0.0025)(0.5)}{0.02625} = \frac{0.00125}{0.02625} = \frac{1}{21}\) \(m=1, n=21\) \(m+n = 1+21 = 22\)
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