CUET · MATHS · PYQ PAPER 2025
In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is:
- A \(\frac{1}{10}\)
- B \(\left(\frac{9}{10}\right)^5\)
- C \(\left(\frac{1}{2}\right)^5\)
- D \(\frac{9}{10}\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{9}{10}\right)^5\)
Step-by-step Solution
Detailed explanation
Non-defective bulbs: \( 100 - 10 = 90 \) Probability of selecting one non-defective bulb: \( P(\text{non-defective}) = \frac{90}{100} = \frac{9}{10} \) Probability that out of a sample of 5 bulbs, none is defective: \( \left(\frac{9}{10}\right)^5 \)
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