CUET · MATHS · PYQ PAPER 2025
If \(y=\sqrt{\sin x+\sqrt{\sin x+\sqrt{\sin x+\cdots \infty}}}\) then \(\frac{d y}{d x}\) equals to
- A \(\frac{-\cos x}{2 y-1}\)
- B \(\frac{\cos x}{2 y-1}\)
- C \(\frac{\sin x}{1-2 y}\)
- D \(\frac{1-2 y}{\cos x}\)
Answer & Solution
Correct Answer
(B) \(\frac{\cos x}{2 y-1}\)
Step-by-step Solution
Detailed explanation
\(y=\sqrt{\sin x+y}\) \(y^2=\sin x+y\) \(2y \frac{dy}{dx} = \cos x + \frac{dy}{dx}\) \((2y-1)\frac{dy}{dx} = \cos x\) \(\frac{dy}{dx} = \frac{\cos x}{2y-1}\)
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