CUET · MATHS · PYQ PAPER 2023
If \(y = x + \tan x\), then value of \(\frac{d^2y}{dx^2}\) at \(x = \frac{\pi}{4}\) is:
- A 1
- B 2
- C 4
- D 2\(\sqrt{2}\)
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
\( \frac{dy}{dx} = 1 + \sec^2 x \) \( \frac{d^2y}{dx^2} = 2\sec x (\sec x \tan x) = 2\sec^2 x \tan x \) \( \frac{d^2y}{dx^2} \Big|_{x = \frac{\pi}{4}} = 2\left(\sec \frac{\pi}{4}\right)^2 \tan \frac{\pi}{4} = 2(\sqrt{2})^2 (1) = 4 \)
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