CUET · MATHS · PYQ PAPER 2023
If \(y=\log \left(x+\sqrt{x^2+a^2}\right)\) then \(\frac{d y}{d x}\) =
- A \(\frac{1}{\sqrt{x^2+a^2}}\)
- B \(\sqrt{x^2+a^2}\)
- C \(\frac{-1}{\sqrt{x^2+a^2}}\)
- D \(-\sqrt{x^2+a^2}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{x^2+a^2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x} = \frac{1}{x+\sqrt{x^2+a^2}} \cdot \frac{d}{dx}\left(x+\sqrt{x^2+a^2}\right)\) \(\frac{d y}{d x} = \frac{1}{x+\sqrt{x^2+a^2}} \cdot \left(1 + \frac{1}{2\sqrt{x^2+a^2}} \cdot 2x\right)\)…
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