CUET · MATHS · PYQ PAPER 2023
If \(y=\sin x+e^x\), then \(\frac{d^2 x}{d y^2}\) is equal to:
- A \(\frac{\sin x-e^x}{\left(\cos x+e^x\right)^2}\)
- B \(\frac{\sin x-e^x}{\left(\cos x+e^x\right)^3}\)
- C \(\frac{\sin x+e^x}{\left(\cos x-e^x\right)^2}\)
- D \(\left(-\sin x+e^x\right)^{-1}\)
Answer & Solution
Correct Answer
(B) \(\frac{\sin x-e^x}{\left(\cos x+e^x\right)^3}\)
Step-by-step Solution
Detailed explanation
\( \frac{dy}{dx} = \cos x + e^x \) \( \frac{dx}{dy} = \frac{1}{\cos x + e^x} \) \( \frac{d^2 x}{d y^2} = \frac{d}{dx} \left( \frac{dx}{dy} \right) \cdot \frac{dx}{dy} \) \( \frac{d^2 x}{d y^2} = \frac{d}{dx} \left( (\cos x + e^x)^{-1} \right) \cdot (\cos x + e^x)^{-1} \)…
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