CUET · MATHS · PYQ PAPER 2023
If \(y=7 \sqrt{x}+3 e^x\), then \(\frac{d^2 y}{d x^2}\) is :
- A \(\frac{7}{2 \sqrt{x}}+3 e^x\)
- B \(\frac{-7}{4} x^{\frac{-3}{2}}+3 e^x\)
- C \(\frac{-7}{4} x^{\frac{3}{2}}+3 e^x\)
- D \(\frac{7}{2} x^{\frac{-3}{2}}+e^x\)
Answer & Solution
Correct Answer
(B) \(\frac{-7}{4} x^{\frac{-3}{2}}+3 e^x\)
Step-by-step Solution
Detailed explanation
\(\frac{dy}{dx} = \frac{7}{2} x^{-\frac{1}{2}} + 3e^x\) \(\frac{d^2y}{dx^2} = \frac{-7}{4} x^{\frac{-3}{2}} + 3e^x\)
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