CUET · MATHS · PYQ PAPER 2025
If y = - 4 a root of \(\left|\begin{array}{lll}y & 2 & 3 \\ 1 & y & 1 \\ 3 & 2 & y\end{array}\right|=0\), then the product of the other two roots is
- A -5
- B 4
- C 0
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
\(\left|\begin{array}{lll}y & 2 & 3 \\ 1 & y & 1 \\ 3 & 2 & y\end{array}\right|=0\) \(y(y^2-2) - 2(y-3) + 3(2-3y) = 0\) \(y^3 - 2y - 2y + 6 + 6 - 9y = 0\) \(y^3 - 13y + 12 = 0\) \(y_1y_2y_3 = -d/a\) \(y_1y_2y_3 = -12/1 = -12\) \(-4 \cdot y_2y_3 = -12\) \(y_2y_3 = 3\)
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