CUET · MATHS · PYQ PAPER 2025
If \(y=\sqrt{2024 x+2025}\), then which of the following is correct?
- A \(y \frac{d^2 y}{d x^2}-2 \frac{d y}{d x}=0\)
- B \(y \frac{d^2 y}{d x^2}-2\left(\frac{d y}{d x}\right)^2=0\)
- C \(y \frac{d^2 y}{d x^2}+x\left(\frac{d y}{d x}\right)^2=0\)
- D \(y \frac{d^2 y}{d x^2}+\left(\frac{d y}{d x}\right)^2=0\)
Answer & Solution
Correct Answer
(D) \(y \frac{d^2 y}{d x^2}+\left(\frac{d y}{d x}\right)^2=0\)
Step-by-step Solution
Detailed explanation
\(y^2 = 2024x+2025\) \(2y \frac{dy}{dx} = 2024\) \(2\left(\frac{dy}{dx}\right)^2 + 2y \frac{d^2y}{dx^2} = 0\) \(y \frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 = 0\)
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