CUET · MATHS · PYQ PAPER 2025
If \(y^{\frac{1}{m}}+y^{-\frac{1}{m}}=2 x\), then the value of \(\left(x^2-1\right) \frac{d^2 y}{d x^2}+x \frac{d y}{d x}\) is :
- A \(0\)
- B \(m y\)
- C \(m^2 y\)
- D \(m^2\)
Answer & Solution
Correct Answer
(C) \(m^2 y\)
Step-by-step Solution
Detailed explanation
\( \frac{1}{m} y^{\frac{1}{m}-1} \frac{dy}{dx} - \frac{1}{m} y^{-\frac{1}{m}-1} \frac{dy}{dx} = 2 \) \( \frac{1}{m y} \frac{dy}{dx} (y^{\frac{1}{m}} - y^{-\frac{1}{m}}) = 2 \)…
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