CUET · MATHS · PYQ PAPER 2023
If \(y=\frac{1}{2} x \sqrt{a^2-x^2}+\frac{a^2}{2} \sin ^{-1}\left(\frac{x}{a}\right)\), then \(\frac{d y}{d x}=\)
- A \(\sqrt{a^2-x^2}\)
- B \(\sqrt{a^2+x^2}\)
- C \(\frac{1}{\sqrt{a^2-x^2}}\)
- D \(\frac{1}{\sqrt{a^2+x^2}}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{a^2-x^2}\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=\frac{1}{2}\left(1 \cdot \sqrt{a^2-x^2}+x \cdot \frac{-2x}{2 \sqrt{a^2-x^2}}\right)+\frac{a^2}{2} \cdot \frac{1}{\sqrt{1-\left(\frac{x}{a}\right)^2}} \cdot \frac{1}{a}\)…
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