CUET · MATHS · PYQ PAPER 2025
If \(y=\frac{1}{1+x^{b-a}+x^{a-a}}+\frac{1}{1+x^{a-b}+x^{a-b}}+\frac{1}{1+x^{a-c}+x^{b-c}}\) then \(\frac{d^2 y}{d x^2}\) is:
- A \(x^a+x^b+x^e\)
- B \(\left(x^a+x^b+x^a\right)\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{e}\right)\)
- C 0
- D 1
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\(y=\frac{x^a}{x^a+x^{b}+x^{c}}+\frac{x^{b}}{x^{a}+x^{b}+x^{c}}+\frac{x^{c}}{x^{a}+x^{b}+x^{c}}\) \(y=\frac{x^a+x^{b}+x^{c}}{x^a+x^{b}+x^{c}}\) \(y=1\) \(\frac{dy}{dx}=0\) \(\frac{d^2y}{dx^2}=0\)
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