CUET · MATHS · PYQ PAPER 2025
If \(x \neq y \neq z\) then \(\left|\begin{array}{lll}1 & x & x^2 \\ 1 & y & y^2 \\ 1 & z & z^2\end{array}\right|\) is equal to
- A \(x+y+z\)
- B \(x y z\)
- C \((x-y)(y-z)(z-x)\)
- D 0
Answer & Solution
Correct Answer
(C) \((x-y)(y-z)(z-x)\)
Step-by-step Solution
Detailed explanation
\( \left| \begin{array}{lll} 1 & x & x^2 \\ 1 & y & y^2 \\ 1 & z & z^2 \end{array} \right| = (x-y)(y-z)(z-x) \)
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