CUET · MATHS · PYQ PAPER 2025
If \(x, y, z\) are non-zero numbers, then the inverse of matrix \(\mathrm{A}=\left[\begin{array}{lll}x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z\end{array}\right]\) is
- A \(\left[\begin{array}{ccc}\frac{1}{x} & 0 & 0 \\ 0 & \frac{1}{y} & 0 \\ 0 & 0 & \frac{1}{z}\end{array}\right]\)
- B \(\left[\begin{array}{ccc}\frac{1}{y z} & 0 & 0 \\ 0 & \frac{1}{x z} & 0 \\ 0 & 0 & \frac{1}{x y}\end{array}\right]\)
- C \(\left[\begin{array}{ccc}\frac{1}{x^2 y z} & 0 & 0 \\ 0 & \frac{1}{x y^2 z} & 0 \\ 0 & 0 & \frac{1}{x y z^2}\end{array}\right]\)
- D \(\left[\begin{array}{ccc}\frac{1}{x y z} & 0 & 0 \\ 0 & \frac{1}{x y z} & 0 \\ 0 & 0 & \frac{1}{x y z}\end{array}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\begin{array}{ccc}\frac{1}{x} & 0 & 0 \\ 0 & \frac{1}{y} & 0 \\ 0 & 0 & \frac{1}{z}\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A^{-1} = \left[\begin{array}{ccc} \frac{1}{x} & 0 & 0 \\ 0 & \frac{1}{y} & 0 \\ 0 & 0 & \frac{1}{z} \end{array}\right]\)
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