CUET · MATHS · PYQ PAPER 2025
If \(x y=e^{(x-y)}\), then \(\frac{d y}{d x}\) is equal to:
- A \(\frac{e^{x-y}+y}{x+e^{x-y}}\)
- B \(\frac{e^{x-y}-y}{x+e^{x-y}}\)
- C \(\frac{e^{x-y}-y}{x-e^{x-y}}\)
- D \(\frac{e^{x-y}+y}{x-e^{x-y}}\)
Answer & Solution
Correct Answer
(B) \(\frac{e^{x-y}-y}{x+e^{x-y}}\)
Step-by-step Solution
Detailed explanation
\( \frac{d}{dx}(xy) = \frac{d}{dx}(e^{x-y}) \) \( y + x\frac{dy}{dx} = e^{x-y}(1 - \frac{dy}{dx}) \) \( y + x\frac{dy}{dx} = e^{x-y} - e^{x-y}\frac{dy}{dx} \) \( x\frac{dy}{dx} + e^{x-y}\frac{dy}{dx} = e^{x-y} - y \) \( \frac{dy}{dx}(x + e^{x-y}) = e^{x-y} - y \)…
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