CUET · MATHS · PYQ PAPER 2025
If \(x, y\) and \(z\) are non-zero distinct numbers, then \(\left|\begin{array}{ccc}x+y & y+z & z+x \\ z & x & y \\ 1 & 1 & 1\end{array}\right|\) is equal to
- A \(x+y+z\)
- B \(2(x+y+z)\)
- C 1
- D \(0\)
Answer & Solution
Correct Answer
(D) \(0\)
Step-by-step Solution
Detailed explanation
\( R_1 \rightarrow R_1 + R_2 \) \( \left|\begin{array}{ccc}x+y+z & x+y+z & x+y+z \\ z & x & y \\ 1 & 1 & 1\end{array}\right| \) \( = (x+y+z) \left|\begin{array}{ccc}1 & 1 & 1 \\ z & x & y \\ 1 & 1 & 1\end{array}\right| \)…
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