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CUET · MATHS · PYQ PAPER 2023

If x is real, the minimum value of \(x^2-8 x+17\) is:

  1. A -1
  2. B 0
  3. C 1
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(C) 1

Step-by-step Solution

Detailed explanation

\(x^2-8 x+17 = (x^2-8 x+16) + 1\) \(= (x-4)^2 + 1\) Minimum value \( = 0 + 1 = 1\)
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