CUET · MATHS · PYQ PAPER 2025
If \(x\) is real, the minimum value of \(x^2-8 x+20\) is :
- A 4
- B 2
- C 0
- D \(-1\)
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
\(x^2-8 x+20 = (x-4)^2+4\) Minimum value = \(0+4=4\)
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