CUET · MATHS · PYQ PAPER 2025
If \(x=e^{\cos 2 t}, y=e^{\sin 2 t}\), then \(\frac{d y}{d x}\) equals to
- A \(\frac{y \log _e x}{x \log _e y}\)
- B \(\frac{x \log _e x}{y \log _e y}\)
- C \(-\frac{y \log _e x}{x \log _e y}\)
- D \(-\frac{x \log _e x}{y \log _e y}\)
Answer & Solution
Correct Answer
(C) \(-\frac{y \log _e x}{x \log _e y}\)
Step-by-step Solution
Detailed explanation
\(\frac{dx}{dt} = e^{\cos 2t} \cdot (-2\sin 2t) = -2x \log y\) \(\frac{dy}{dt} = e^{\sin 2t} \cdot (2\cos 2t) = 2y \log x\) \(\frac{dy}{dx} = \frac{dy/dt}{dx/dt} = \frac{2y \log x}{-2x \log y} = -\frac{y \log x}{x \log y}\)
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