CUET · MATHS · PYQ PAPER 2025
If \(x=a \cos \alpha+b \sin \alpha\) and \(y=a \sin \alpha-b \cos \alpha\), then \(\left(x \frac{d y}{d x}-y^2 \frac{d^2 y}{d x^2}\right)\) is equal to :
- A \(0\)
- B 2
- C \(x\)
- D \(y\)
Answer & Solution
Correct Answer
(D) \(y\)
Step-by-step Solution
Detailed explanation
\(\frac{dx}{d\alpha} = -a \sin \alpha + b \cos \alpha = -y\) \(\frac{dy}{d\alpha} = a \cos \alpha + b \sin \alpha = x\) \(\frac{dy}{dx} = \frac{dy/d\alpha}{dx/d\alpha} = \frac{x}{-y} = -\frac{x}{y}\)…
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