CUET · MATHS · PYQ PAPER 2025
If \(x=4 t\) and \(y=\frac{4}{t}\), then \(\frac{d^2 y}{d x^2}\) is
- A \(-\frac{1}{t^2}\)
- B \(\frac{2}{t^3}\)
- C \(\frac{1}{2 t^3}\)
- D \(\frac{8}{t^3}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2 t^3}\)
Step-by-step Solution
Detailed explanation
\( \frac{dx}{dt} = 4 \) \( \frac{dy}{dt} = -\frac{4}{t^2} \) \( \frac{dy}{dx} = \frac{dy/dt}{dx/dt} = \frac{-4/t^2}{4} = -\frac{1}{t^2} \) \( \frac{d}{dt} \left( \frac{dy}{dx} \right) = \frac{d}{dt} \left( -t^{-2} \right) = 2t^{-3} = \frac{2}{t^3} \)…
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