CUET · MATHS · PYQ PAPER 2025
If \(x^2-y^2=1\), then which of the following is correct?
(A) \(\left(x^2-1\right)\left(\frac{d y}{d x}\right)^2=x^2\)
(B) \(\left(x^2-1\right)\left(\frac{d^2 y}{d x^2}\right)^2=x^2\)
(C) \(\left(x^2-1\right)^3\left(\frac{d^2 y}{d x^2}\right)^2=x^2\)
(D) \(\left(x^2-1\right)^3\left(\frac{d^2 y}{d x^2}\right)^2=1\)
Choose the correct answer from the options given below :
- A (B) and (D) only
- B (A), (B) and (C) only
- C (A) and (D) only
- D (B) and (C) only
Answer & Solution
Correct Answer
(C) (A) and (D) only
Step-by-step Solution
Detailed explanation
\(x^2-y^2=1\) \(2x - 2y \frac{dy}{dx} = 0 \implies \frac{dy}{dx} = \frac{x}{y}\) \(\left(\frac{dy}{dx}\right)^2 = \frac{x^2}{y^2} = \frac{x^2}{x^2-1}\) For (A): \(\left(x^2-1\right)\left(\frac{dy}{dx}\right)^2 = \left(x^2-1\right)\frac{x^2}{x^2-1} = x^2\). Option (A) is correct.…
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