If we take \(8\) identical slips of paper and write the number \(0\) on one of them, the number \(1\) on three of the slips, the number \(2\) on three of the slips and the number \(3\) on one of the slips. These slips are folded, put in a box and roughly mixed. One slip is drawn at random from the box. If \(X\) is the random variable denoting the number written on the drawn slip, the variance of \(X\) is:

The corner points of the bounded feasible region determined by the system of linear inequalities are (0, 0), (4, 0), (2, 4) and (0, 5). If maximum value of z = ax + by, where a, b > 0 occurs at both (2, 4) and (4, 0) then

If \(A(3,2), B(1,-1)\) and \(C(2,1)\) are three vertices of a parallelogram \(A B C D\), then its area (in sq. units) is equal to

The value of \(\tan ^{-1}(1)+\cos ^{-1}\left(-\frac{\sqrt{3}}{2}\right)+\sin ^{-1}\left(\frac{1}{2}\right)\) is:

Three numbers are chosen at random without replacement from {1, 2, 3, 4, 5, 6, 7, 8}. The probability that their minimum is 3, (given that their maximum is 6)is:

The integral \(\int e^x\left(\frac{x-1}{2 x^2}\right) d x\) is equal to:

If \(\int \frac{d x}{(x+1)(x+2)}=\int \frac{A}{x+1} d x+\int \frac{B}{x+2} d x\), then \(A+B=\)

The reason for the survival of the melanised moth, during the post-industrialization period in England was:

The atomic numbers and mass numbers of the nuclei of hydrogen, deuterium and tritium, respectively are in the ratio

Full form of ELISA is:

Answer the question on the basis of passage given below:
Second period elements of p-Block differs from the rest of their group members due to their small atomic size, high electronegativity, high ionization enthalpy and absence of d-orbitals. The elements from the second period like C, N, O have unique property of forming \(p \pi-p \pi\) multiple bonds whereas other heavier elements of p-block form \(d \pi-p \pi\) multiple bonds. This changes the properties of second period elements to great extent. Also the single bond strength of the p-block elements with their own atoms gets affected by their atomic size and presence of lone pairs.
Inert pair effect also affects the properties of the p-Block elements especially for those elements which are present from 4th period onward and this happens due to poor screening effect of inner (n-1)d subshell electrons.
Catenation tendency of Nitrogen is weaker than Phosphorus, because

Two point charges of 1 C each are separated from each other by a distance of 1 m in vacuum.
The force of interaction between them is:

In an electromagnetic wave, the ratio of energy densities of electric and magnetic fields is :