CUET · MATHS · PYQ PAPER 2023
If \(u=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)\) and \(v=\tan ^{-1} x, x \in(-1,1)\), then \(\frac{d u}{d v}\) is equal to:
- A 3
- B \(0\)
- C 1
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
\(u = 2\tan^{-1}x\) \(u = 2v\) \(\frac{du}{dv} = 2\)
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