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CUET · MATHS · PYQ PAPER 2023

If \(u=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)\) and \(v=\tan ^{-1} x, x \in(-1,1)\), then \(\frac{d u}{d v}\) is equal to:

  1. A 3
  2. B \(0\)
  3. C 1
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(D) 2

Step-by-step Solution

Detailed explanation

\(u = 2\tan^{-1}x\) \(u = 2v\) \(\frac{du}{dv} = 2\)
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