CUET · MATHS · PYQ PAPER 2025
If three balls are drawn one by one without replacement from a bag containing 5 white and 4 red balls, then the probability distribution of the number of white balls drawn is
- A
(X) 0 1 2 3 (P(X) 30/91 45/91 15/91 1/91 - B
(X) 0 1 2 3 (P(X) 1/21 5/14 10/21 5/42 - C
(X) 0 1 2 3 (P(X) 1/8 3/8 3/8 1/8 - D
(X) 0 1 2 3 (P(X) 12/19 16/35 16/35 3/95
Answer & Solution
Correct Answer
(B) (X) 0 1 2 3 (P(X) 1/21 5/14 10/21 5/42
Step-by-step Solution
Detailed explanation
Total ways to draw 3 balls from 9: \( \binom{9}{3} = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} = 84 \) \( P(X=0) = \frac{\binom{5}{0} \binom{4}{3}}{\binom{9}{3}} = \frac{1 \times 4}{84} = \frac{4}{84} = \frac{1}{21} \)…
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