CUET · MATHS · PYQ PAPER 2023
If the tangent to the curve \(y^2 + 3x - 7 = 0\) at the point (h, k) is parallel to the line x - y = 4, then the value of k is:
- A \(-\frac{2}{3}\)
- B \(-\frac{3}{2}\)
- C \(\frac{3}{2}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(B) \(-\frac{3}{2}\)
Step-by-step Solution
Detailed explanation
\(y^2 + 3x - 7 = 0\) \(2y \frac{dy}{dx} + 3 = 0 \Rightarrow \frac{dy}{dx} = -\frac{3}{2y}\) Slope of tangent at (h, k) is \(m_t = -\frac{3}{2k}\). Slope of line \(x - y = 4\) is \(m_l = 1\). Since tangent is parallel to the line, \(m_t = m_l\): \(-\frac{3}{2k} = 1\)…
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