CUET · MATHS · PYQ PAPER 2025
If the system of equations
\( \begin{array}{l} x+2 y+3 z=10 \\ -x+y+\lambda z=20 \\ 2 x+3 y+\lambda z=0 \end{array} \)
does not possess a unique solution, then \(\lambda\) is equal to
- A 1
- B \(\frac{15}{4}\)
- C \(\frac{4}{15}\)
- D -1
Answer & Solution
Correct Answer
(B) \(\frac{15}{4}\)
Step-by-step Solution
Detailed explanation
\( \det \begin{pmatrix} 1 & 2 & 3 \\ -1 & 1 & \lambda \\ 2 & 3 & \lambda \end{pmatrix} = 0 \) \( 1(\lambda - 3\lambda) - 2(-\lambda - 2\lambda) + 3(-3 - 2) = 0 \) \( -2\lambda + 6\lambda - 15 = 0 \) \( 4\lambda = 15 \) \( \lambda = \frac{15}{4} \)
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