CUET · MATHS · PYQ PAPER 2025
If the sum and difference of squares of mean and variance of a Binomial distribution is \(\frac{225}{256}\) and \(\frac{63}{256}\) respectively, the \(P(X \geq 2)\) is :
- A \(\frac{81}{256}\)
- B \(\frac{9}{16}\)
- C \(\frac{ 5 }{ 3 2 }\)
- D \(\frac{9}{256}\)
Answer & Solution
Correct Answer
(C) \(\frac{ 5 }{ 3 2 }\)
Step-by-step Solution
Detailed explanation
\( \mu^2 + (\sigma^2)^2 = \frac{225}{256} \) \( \mu^2 - (\sigma^2)^2 = \frac{63}{256} \) \( 2\mu^2 = \frac{225+63}{256} = \frac{288}{256} \Rightarrow \mu^2 = \frac{144}{256} \) \( \mu = \sqrt{\frac{144}{256}} = \frac{12}{16} = \frac{3}{4} \)…
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