CUET · MATHS · PYQ PAPER 2025
If the probability of two successes is 9 times the probability of 3 successes in 3 trials of a binomial distribution, then the probability of success in each trial is:
- A \(\frac{1}{4}\)
- B \(\frac{1}{8}\)
- C \(\frac{3}{4}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
\(C(3,2)p^2(1-p)^1 = 9 \cdot C(3,3)p^3(1-p)^0\) \(3p^2(1-p) = 9p^3\) \(1-p = 3p\) \(1 = 4p\) \(p = \frac{1}{4}\)
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