CUET · MATHS · PYQ PAPER 2025
If the minimum value of \(a\) is \(-\frac{k}{2}\), such that the function \(f(x)=x^2+a x+5\) is increasing in \([1,2]\). Then value of \(k\) is
- A -4
- B 2
- C 4
- D -2
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
\(f'(x) = 2x+a\) \(2x+a \ge 0\) for \(x \in [1,2]\) \(2(1)+a \ge 0 \implies a \ge -2\) Minimum value of \(a\) is \(-2\) \(-\frac{k}{2} = -2\) \(k = 4\)
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