CUET · MATHS · PYQ PAPER 2025
If the maximum value of the function \(f(x)=\frac{\log _e x}{x}, x>0\) occurs at \(x=a\), then \(a^2 f^{\prime \prime}(a)\) is equal to:
- A \(-\frac{5}{e}\)
- B \(-\frac{1}{e}\)
- C \(-\frac{1}{e^3}\)
- D \(-5 e^3\)
Answer & Solution
Correct Answer
(B) \(-\frac{1}{e}\)
Step-by-step Solution
Detailed explanation
\(f'(x) = \frac{\frac{1}{x} \cdot x - \log _e x \cdot 1}{x^2} = \frac{1 - \log _e x}{x^2}\) \(f'(x) = 0 \Rightarrow 1 - \log _e x = 0 \Rightarrow \log _e x = 1 \Rightarrow x = e\) \(a = e\)…
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