CUET · MATHS · PYQ PAPER 2025
If the matrix \(\left[\begin{array}{ccc}-1 & x-y & 4 \\ 2 & 0 & 5 \\ x+y & z & 6\end{array}\right]\) is symmetric, then \(x+3 y+2 z\) is equal to
- A 16
- B 18
- C 14
- D 10
Answer & Solution
Correct Answer
(A) 16
Step-by-step Solution
Detailed explanation
\(a_{12} = a_{21} \implies x-y = 2\) \(a_{13} = a_{31} \implies x+y = 4\) \(a_{23} = a_{32} \implies z = 5\) \(x-y=2, x+y=4 \implies x=3, y=1\) \(x+3y+2z = 3+3(1)+2(5) = 3+3+10 = 16\)
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