CUET · MATHS · PYQ PAPER 2023
If the matrix A = \(\left[\begin{array}{cc}\cos \theta & \sin \theta \\ -\sin \theta & \cos \theta\end{array}\right]\), then \(A ^2\) is equal to:
- A \(\left[\begin{array}{cc}\cos 2 \theta & \sin 2 \theta \\ -\sin 2 \theta & \cos 2 \theta\end{array}\right]\)
- B \(\left[\begin{array}{cc}\cos ^2 \theta & \sin ^2 \theta \\ -\sin ^2 \theta & \cos ^2 \theta\end{array}\right]\)
- C \(\left[\begin{array}{cc}\cos \theta^2 & \sin \theta^2 \\ -\sin \theta^2 & \cos \theta^2\end{array}\right]\)
- D \(\left[\begin{array}{ll}\cos \theta+\sin \theta & \cos \theta-\sin \theta \\ \sin \theta-\cos \theta & \cos \theta+\sin \theta\end{array}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\begin{array}{cc}\cos 2 \theta & \sin 2 \theta \\ -\sin 2 \theta & \cos 2 \theta\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A^2 = \left[ \begin{array}{cc} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{array} \right] \left[ \begin{array}{cc} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{array} \right]\)…
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