CUET · MATHS · PYQ PAPER 2025
If the lines \(\frac{x-5}{5 \lambda+2}=\frac{2-y}{5}=\frac{1-z}{-1}\) and \(x=\frac{y+1 / 2}{2 \lambda}=\frac{z-1}{3}\) are perpendicular, then the value of \(\lambda\) is equal to
- A -1
- B 1
- C 5
- D \(\frac{1}{5}\)
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
For perpendicular lines, \(\vec{d_1} \cdot \vec{d_2} = 0\): \((5 \lambda+2)(1) + (-5)(2 \lambda) + (1)(3) = 0\) \(5 \lambda+2 - 10 \lambda + 3 = 0\) \(-5 \lambda + 5 = 0\) \(\lambda = 1\)
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