CUET · MATHS · PYQ PAPER 2023
If the lines \(\frac{1-x}{3}=\frac{2 y-4}{4 K}=\frac{z-3}{2}\) and \(\frac{x-1}{3 K}=\frac{1-y}{-1}=\frac{6-z}{5}\) are perpendicular, then the value of \(K\) is :
- A \(\frac{10}{7}\)
- B \(\frac{7}{10}\)
- C \(-\frac{7}{10}\)
- D \(-\frac{10}{7}\)
Answer & Solution
Correct Answer
(D) \(-\frac{10}{7}\)
Step-by-step Solution
Detailed explanation
Direction vector for line 1: \(\vec{d_1} = \langle -3, 2K, 2 \rangle\) Direction vector for line 2: \(\vec{d_2} = \langle 3K, 1, -5 \rangle\) \(\vec{d_1} \cdot \vec{d_2} = 0\) \((-3)(3K) + (2K)(1) + (2)(-5) = 0\) \(-9K + 2K - 10 = 0\) \(-7K = 10\) \(K = -\frac{10}{7}\)
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