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CUET · MATHS · PYQ PAPER 2025

If the integral \(I=\int\left\{\log _e\left(\log _e x\right)^2+\frac{\alpha}{\log _e x}\right\} d x=x \log _e\left(\log _e x\right)^2+C\), where \(C\) is constant of integration. Then the value of \(\alpha\) is :

  1. A 0
  2. B -1
  3. C -2
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(D) 2

Step-by-step Solution

Detailed explanation

\(\frac{d}{dx}\left[x \log _e\left(\log _e x\right)^2\right] = \log _e\left(\log _e x\right)^2 + x \cdot \frac{d}{dx}\left[\log _e\left(\log _e x\right)^2\right]\)…