CUET · MATHS · PYQ PAPER 2025
If the function
\(f(x)=\left\{\begin{array}{ll}a x+2, & x \leq 1 \\x^2+3 x+b, & x>1\end{array}\right.\)
is differentiable at \(x=1\), then the value of \((2 a+b)\) is
- A 13
- B 11
- C 16
- D 8
Answer & Solution
Correct Answer
(A) 13
Step-by-step Solution
Detailed explanation
Continuity at \(x=1\): \(a(1)+2 = (1)^2+3(1)+b \implies a+2 = 4+b \implies a-b=2\) Differentiability at \(x=1\): \(f'\_(1) = f'\_+(1)\) \(a = 2(1)+3 \implies a=5\) \(5-b=2 \implies b=3\) \(2a+b = 2(5)+3 = 10+3=13\)
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