ExamBro
ExamBro
CUET · MATHS · PYQ PAPER 2023

If the function \(f(x)=\left\{\begin{array}{ll}\frac{\sin 5 x}{3 x}, & x \neq 0 \\ \frac{k}{3}, & x=0\end{array}\right.\) is continuous at \(x=0\), then \(k^2-2 k+10\) is equal to:

  1. A 35
  2. B 25
  3. C 40
  4. D 15
Verified Solution

Answer & Solution

Correct Answer

(B) 25

Step-by-step Solution

Detailed explanation

\(\lim_{x \to 0} f(x) = \lim_{x \to 0} \frac{\sin 5 x}{3 x} = \frac{5}{3}\) \(f(0) = \frac{k}{3}\) \(\frac{k}{3} = \frac{5}{3} \Rightarrow k = 5\) \(k^2-2 k+10 = (5)^2 - 2(5) + 10 = 25 - 10 + 10 = 25\)
From CUET
Explore more questions on app