CUET · MATHS · PYQ PAPER 2023
If the function \(f(x)=\left\{\begin{array}{ll}\frac{\sin 5 x}{3 x}, & x \neq 0 \\ \frac{k}{3}, & x=0\end{array}\right.\) is continuous at \(x=0\), then \(k^2-2 k+10\) is equal to:
- A 35
- B 25
- C 40
- D 15
Answer & Solution
Correct Answer
(B) 25
Step-by-step Solution
Detailed explanation
\(\lim_{x \to 0} f(x) = \lim_{x \to 0} \frac{\sin 5 x}{3 x} = \frac{5}{3}\) \(f(0) = \frac{k}{3}\) \(\frac{k}{3} = \frac{5}{3} \Rightarrow k = 5\) \(k^2-2 k+10 = (5)^2 - 2(5) + 10 = 25 - 10 + 10 = 25\)
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