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CUET · MATHS · PYQ PAPER 2025

If the function defined by \(f(x)=\left\{\begin{array}{ll}k x^2+1, & \text { if } x \leq 1 \\ 2, & \text { if } x>1\end{array}\right.\) is continuous at \(x=1\), then \(k\) is equal to

  1. A 2
  2. B 3
  3. C \(-1\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(D) 1

Step-by-step Solution

Detailed explanation

\( \lim_{x \to 1^-} f(x) = \lim_{x \to 1^+} f(x) \) \( k(1)^2+1 = 2 \) \( k+1 = 2 \) \( k = 1 \)