CUET · MATHS · PYQ PAPER 2023
If the elementary column transformation \(C_1 \rightarrow 2 C_1\) is carried out on the following matrix equation.
\(\left[\begin{array}{ll}1 & 3 \\ 2 & 4\end{array}\right]\left[\begin{array}{cc}-1 & 2 \\ 5 & 0\end{array}\right]=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\) Then the transformed equation will be:
- A \(\left[\begin{array}{ll}2 & 3 \\ 4 & 4\end{array}\right]\left[\begin{array}{cc}-1 & 2 \\ 5 & 0\end{array}\right]=\left[\begin{array}{cc}2 a & b \\ 2 c & d\end{array}\right]\)
- B \(\left[\begin{array}{ll}1 & 3 \\ 2 & 4\end{array}\right]\left[\begin{array}{cc}-2 & 2 \\ 10 & 0\end{array}\right]=\left[\begin{array}{ll}2 a & b \\ 2 c & d\end{array}\right]\)
- C \(\left[\begin{array}{ll}2 & 3 \\ 4 & 4\end{array}\right]\left[\begin{array}{cc}-2 & 2 \\ 10 & 0\end{array}\right]=\left[\begin{array}{cc}2 a & b \\ 2 c & d\end{array}\right]\)
- D \(\left[\begin{array}{ll}2 & 3 \\ 4 & 4\end{array}\right]\left[\begin{array}{cc}-1 & 2 \\ 5 & 0\end{array}\right]=\left[\begin{array}{ll}2 a & 2 b \\ 2 c & 2 d\end{array}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\begin{array}{ll}1 & 3 \\ 2 & 4\end{array}\right]\left[\begin{array}{cc}-2 & 2 \\ 10 & 0\end{array}\right]=\left[\begin{array}{ll}2 a & b \\ 2 c & d\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(E = \left[\begin{array}{ll}2 & 0 \\ 0 & 1\end{array}\right]\)…
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