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CUET · MATHS · PYQ PAPER 2025

If the area above x - axis, bounded by the curves \((y = 3^{\beta x}), \; x = 0\) and \(x = 3\) is \(\frac{(26)}{\log(e)} 3\), then the value of \(\beta\) is:

  1. A \(\beta= 2\)
  2. B \(\beta=1\)
  3. C \(\beta=-1\)
  4. D \(\beta=\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\beta=1\)

Step-by-step Solution

Detailed explanation

\(A = \int_{0}^{3} 3^{\beta x} dx\) \(A = \left[ \frac{3^{\beta x}}{\beta \ln 3} \right]_{0}^{3} = \frac{3^{3\beta} - 3^0}{\beta \ln 3} = \frac{3^{3\beta} - 1}{\beta \ln 3}\) Given \(A = \frac{26}{\ln 3}\) \(\frac{3^{3\beta} - 1}{\beta \ln 3} = \frac{26}{\ln 3}\)…
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