CUET · MATHS · PYQ PAPER 2025
If the area above x - axis, bounded by the curves \((y = 3^{\beta x}), \; x = 0\) and \(x = 3\) is \(\frac{(26)}{\log(e)} 3\), then the value of \(\beta\) is:
- A \(\beta= 2\)
- B \(\beta=1\)
- C \(\beta=-1\)
- D \(\beta=\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) \(\beta=1\)
Step-by-step Solution
Detailed explanation
\(A = \int_{0}^{3} 3^{\beta x} dx\) \(A = \left[ \frac{3^{\beta x}}{\beta \ln 3} \right]_{0}^{3} = \frac{3^{3\beta} - 3^0}{\beta \ln 3} = \frac{3^{3\beta} - 1}{\beta \ln 3}\) Given \(A = \frac{26}{\ln 3}\) \(\frac{3^{3\beta} - 1}{\beta \ln 3} = \frac{26}{\ln 3}\)…
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