CUET · MATHS · PYQ PAPER 2025
If \(P, Q\) and \(R\) are three singular matrices given by
\(P=\left[\begin{array}{cc}2 & 3 a \\4 & 3\end{array}\right], Q=\left[\begin{array}{cc}b & 5 \\2 a & 6\end{array}\right]\)
and \(R=\left[\begin{array}{cc}a^2+b^2-c & 1-c \\ c+1 & c\end{array}\right]\), then the value of \((2 a+6 b+17 c)\) is:
- A \(30\)
- B \(18\)
- C \(34\)
- D \(24\)
Answer & Solution
Correct Answer
(D) \(24\)
Step-by-step Solution
Detailed explanation
\(2(3) - 3a(4) = 0 \implies 6 - 12a = 0 \implies a = \frac{1}{2}\) \(b(6) - 5(2a) = 0 \implies 6b - 10\left(\frac{1}{2}\right) = 0 \implies 6b - 5 = 0 \implies b = \frac{5}{6}\) \((a^2+b^2-c)c - (1-c)(c+1) = 0\) \((a^2+b^2)c - c^2 - (1 - c^2) = 0 \implies (a^2+b^2)c - 1 = 0\)…
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