CUET · MATHS · PYQ PAPER 2023
If matrix \(A=\left[a_{i j}\right]_{2 \times 2}\) where \(a_{i j}=\left\{\begin{array}{l}1, i \neq j \\ 0, i=j\end{array}\right.\) then \(A^3\) is equal to :
- A A
- B O
- C I
- D \(A^T\)
Answer & Solution
Correct Answer
(A) A
Step-by-step Solution
Detailed explanation
\(A = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}\) \(A^2 = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} = I\) \(A^3 = A^2 \cdot A = I \cdot A = A\)
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