CUET · MATHS · PYQ PAPER 2025
If \(M=\left[\begin{array}{c}2 \\ -1 \\ 3\end{array}\right]\) and \(N=\left[\begin{array}{lll}7 & 1 & -4\end{array}\right]\), then \((M N)^T\) will be equal to:
- A \(\left[\begin{array}{ccc}7 & 1 & -4 \\ 2 & -1 & 3 \\ 9 & 0 & -1\end{array}\right]\)
- B \(\left[\begin{array}{ccc}14 & 2 & -8 \\ -7 & -1 & 4 \\ 21 & 3 & -12\end{array}\right]\)
- C \(\left[\begin{array}{ccc}14 & -7 & 21 \\ 2 & -1 & 3 \\ 1 & 3 & -12\end{array}\right]\)
- D \(\left[\begin{array}{ccc}14 & -7 & 21 \\ 2 & -1 & 3 \\ -8 & 4 & -12\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{ccc}14 & -7 & 21 \\ 2 & -1 & 3 \\ -8 & 4 & -12\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(M N = \left[\begin{array}{c}2 \\ -1 \\ 3\end{array}\right] \left[\begin{array}{lll}7 & 1 & -4\end{array}\right] = \left[\begin{array}{ccc} 14 & 2 & -8 \\ -7 & -1 & 4 \\ 21 & 3 & -12 \end{array}\right]\)…
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